Cambridge International AS & A Level 9702: Kinematics: Uniform Acceleration & SUVAT Equations | Tutolia Study Library

Derive and apply the 4 kinematic equations for uniformly accelerated motion in 1D and 2D projectile trajectories for Cambridge 9702.

Subject: Physics | Grade Level: Grade 11-12 (AS & A Level) | Curriculum: Cambridge International AS & A Level

Cambridge International AS & A Level: Kinematics: Uniform Acceleration & SUVAT Equations (Physics)

Syllabus Code: 9702 · Topic Code: 2.1 · Level: Grade 11-12 (AS & A Level)

Aligned with official Cambridge International AS & A Level examination standards and assessment objectives.


🎯 Official Syllabus Learning Objectives

Candidates should be able to:


📐 Essential Formulas & Mathematical Equations

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v = u + at

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s = \frac{u + v}{2} t

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s = ut + \frac{1}{2}at^2

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v^2 = u^2 + 2as

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💡 Conceptual Breakdown & Core Revision Notes

Mastering Kinematics: Uniform Acceleration & SUVAT Equations is critical for scoring Grade 9 / A* in Cambridge International AS & A Level Physics. When preparing for exam papers, examiners prioritize precise definitions, proper scientific command-word execution (State, Describe, Explain, Evaluate), and dimensional unit consistency.

Methodical Problem-Solving Framework

  1. List Given Variables: Write down all given quantities with their respective SI units and identify the target variable.
  2. Standardise Units: Always convert non-standard units (e.g. grams to kilograms, centimeters to meters, cm³ to dm³, hours to seconds).
  3. State the Base Formula: Always state the general equation explicitly before substituting numbers to secure method marks.
  4. State Final Value with Units: Quote your final calculated value to the required number of significant figures (typically 2 or 3 significant figures in Cambridge & IB) followed by the correct unit.

⚠️ Examiner Warnings & Common Student Pitfalls

Chief Examiner Advice:

Choose a consistent sign convention (e.g. upwards positive). If upwards is positive, acceleration of free fall g = -9.81 m/s².


📝 Worked Exam Exemplar (Mark Scheme Breakdown)

Question:

A ball is launched from ground level at 24.0 m/s at an angle of 35.0° to the horizontal. Calculate the maximum height reached (g = 9.81 m/s²).

Model Answer & Marking Rubric:

Vertical initial velocity uy = 24.0 * sin(35°) = 13.76 m/s. At max height vy = 0. vy² = uy² - 2gy => 0 = (13.76)² - 2(9.81)y => y = 189.34 / 19.62 = 9.65 m.


🧠 Rapid Active-Recall Study Deck (Spaced Repetition)

Test your immediate retention before leaving this page:

  1. Question: What is the fundamental definition associated with Kinematics: Uniform Acceleration & SUVAT Equations?

Answer: Check the primary learning objective in the checklist above.

  1. Question: Which governing formula links the main physical quantities in this topic?

Answer: `v = u + at`.

  1. Question: What classic trap do examiners frequently set on this topic?

Answer: Choose a consistent sign convention (e.g. upwards positive). If upwards is positive, acceleration of free fall g = -9.81 m/s².