Cambridge IGCSE 0620: Stoichiometry, The Mole Concept & Reacting Masses | Tutolia Study Library

Step-by-step mole conversions, molar gas volume (24 dm³ at RTP), percentage yield, and concentration calculations for IGCSE Chemistry 0620.

Subject: Chemistry | Grade Level: Grade 9-10 (IGCSE) | Curriculum: Cambridge IGCSE

Cambridge IGCSE: Stoichiometry, The Mole Concept & Reacting Masses (Chemistry)

Syllabus Code: 0620 · Topic Code: 3.1 · Level: Grade 9-10 (IGCSE)

Aligned with official Cambridge IGCSE examination standards and assessment objectives.


🎯 Official Syllabus Learning Objectives

Candidates should be able to:


📐 Essential Formulas & Mathematical Equations

$

n = \frac{m}{M_r}

$

$

n = \frac{V \text{ (in dm}^3)}{24}

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$

C = \frac{n}{V \text{ (dm}^3)} = \frac{m}{M_r \cdot V}

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\% \text{ Yield} = \frac{\text{Actual Mass}}{\text{Theoretical Mass}} \times 100\%

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💡 Conceptual Breakdown & Core Revision Notes

Mastering Stoichiometry, The Mole Concept & Reacting Masses is critical for scoring Grade 9 / A* in Cambridge IGCSE Chemistry. When preparing for exam papers, examiners prioritize precise definitions, proper scientific command-word execution (State, Describe, Explain, Evaluate), and dimensional unit consistency.

Methodical Problem-Solving Framework

  1. List Given Variables: Write down all given quantities with their respective SI units and identify the target variable.
  2. Standardise Units: Always convert non-standard units (e.g. grams to kilograms, centimeters to meters, cm³ to dm³, hours to seconds).
  3. State the Base Formula: Always state the general equation explicitly before substituting numbers to secure method marks.
  4. State Final Value with Units: Quote your final calculated value to the required number of significant figures (typically 2 or 3 significant figures in Cambridge & IB) followed by the correct unit.

⚠️ Examiner Warnings & Common Student Pitfalls

Chief Examiner Advice:

Always convert cm³ to dm³ by dividing by 1000 before computing solution concentrations.


📝 Worked Exam Exemplar (Mark Scheme Breakdown)

Question:

Calculate the volume of CO₂ at RTP produced when 10.0 g of CaCO₃ completely decomposes (CaCO₃ -> CaO + CO₂). Mr(CaCO₃) = 100.

Model Answer & Marking Rubric:

Moles of CaCO₃ = 10.0 / 100 = 0.10 mol. Mole ratio CaCO₃:CO₂ = 1:1, so moles of CO₂ = 0.10 mol. Volume = 0.10 * 24 dm³ = 2.4 dm³ (or 2400 cm³).


🧠 Rapid Active-Recall Study Deck (Spaced Repetition)

Test your immediate retention before leaving this page:

  1. Question: What is the fundamental definition associated with Stoichiometry, The Mole Concept & Reacting Masses?

Answer: Check the primary learning objective in the checklist above.

  1. Question: Which governing formula links the main physical quantities in this topic?

Answer: `n = \frac{m}{M_r}`.

  1. Question: What classic trap do examiners frequently set on this topic?

Answer: Always convert cm³ to dm³ by dividing by 1000 before computing solution concentrations.