Cambridge IGCSE 0625: Forces, Resultant Force & Newton’s Three Laws | Tutolia Study Library

Master balanced vs unbalanced forces, Hooke’s law, spring constants, terminal velocity, and F=ma calculations for Cambridge IGCSE 0625.

Subject: Physics | Grade Level: Grade 9-10 (IGCSE) | Curriculum: Cambridge IGCSE

Cambridge IGCSE: Forces, Resultant Force & Newton’s Three Laws (Physics)

Syllabus Code: 0625 · Topic Code: 1.5 · Level: Grade 9-10 (IGCSE)

Aligned with official Cambridge IGCSE examination standards and assessment objectives.


🎯 Official Syllabus Learning Objectives

Candidates should be able to:


📐 Essential Formulas & Mathematical Equations

$

F_{\text{net}} = m \cdot a

$

$

F = k \cdot x

$


💡 Conceptual Breakdown & Core Revision Notes

Mastering Forces, Resultant Force & Newton’s Three Laws is critical for scoring Grade 9 / A* in Cambridge IGCSE Physics. When preparing for exam papers, examiners prioritize precise definitions, proper scientific command-word execution (State, Describe, Explain, Evaluate), and dimensional unit consistency.

Methodical Problem-Solving Framework

  1. List Given Variables: Write down all given quantities with their respective SI units and identify the target variable.
  2. Standardise Units: Always convert non-standard units (e.g. grams to kilograms, centimeters to meters, cm³ to dm³, hours to seconds).
  3. State the Base Formula: Always state the general equation explicitly before substituting numbers to secure method marks.
  4. State Final Value with Units: Quote your final calculated value to the required number of significant figures (typically 2 or 3 significant figures in Cambridge & IB) followed by the correct unit.

⚠️ Examiner Warnings & Common Student Pitfalls

Chief Examiner Advice:

At terminal velocity, acceleration is ZERO because resultant force is zero. Velocity is NOT zero; it is at its constant maximum.


📝 Worked Exam Exemplar (Mark Scheme Breakdown)

Question:

A skydiver of total mass 80 kg experiences an air resistance of 600 N. Taking g = 9.8 m/s², calculate the downward acceleration.

Model Answer & Marking Rubric:

Weight W = 80 * 9.8 = 784 N. Resultant force = 784 - 600 = 184 N downwards. a = F / m = 184 / 80 = 2.3 m/s².


🧠 Rapid Active-Recall Study Deck (Spaced Repetition)

Test your immediate retention before leaving this page:

  1. Question: What is the fundamental definition associated with Forces, Resultant Force & Newton’s Three Laws?

Answer: Check the primary learning objective in the checklist above.

  1. Question: Which governing formula links the main physical quantities in this topic?

Answer: `F_{\text{net}} = m \cdot a`.

  1. Question: What classic trap do examiners frequently set on this topic?

Answer: At terminal velocity, acceleration is ZERO because resultant force is zero. Velocity is NOT zero; it is at its constant maximum.