Cambridge IGCSE 0625: Motion: Speed, Velocity & Acceleration Graphs | Tutolia Study Library

Complete revision of distance-time and velocity-time graphs, calculating gradient, acceleration, and total distance travelled for IGCSE 0625.

Subject: Physics | Grade Level: Grade 9-10 (IGCSE) | Curriculum: Cambridge IGCSE

Cambridge IGCSE: Motion: Speed, Velocity & Acceleration Graphs (Physics)

Syllabus Code: 0625 ยท Topic Code: 1.2 ยท Level: Grade 9-10 (IGCSE)

Aligned with official Cambridge IGCSE examination standards and assessment objectives.


๐ŸŽฏ Official Syllabus Learning Objectives

Candidates should be able to:


๐Ÿ“ Essential Formulas & Mathematical Equations

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v = \frac{\Delta s}{\Delta t}

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a = \frac{v - u}{t}

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\text{Distance} = \text{Area under speed-time graph}

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๐Ÿ’ก Conceptual Breakdown & Core Revision Notes

Mastering Motion: Speed, Velocity & Acceleration Graphs is critical for scoring Grade 9 / A* in Cambridge IGCSE Physics. When preparing for exam papers, examiners prioritize precise definitions, proper scientific command-word execution (State, Describe, Explain, Evaluate), and dimensional unit consistency.

Methodical Problem-Solving Framework

  1. List Given Variables: Write down all given quantities with their respective SI units and identify the target variable.
  2. Standardise Units: Always convert non-standard units (e.g. grams to kilograms, centimeters to meters, cmยณ to dmยณ, hours to seconds).
  3. State the Base Formula: Always state the general equation explicitly before substituting numbers to secure method marks.
  4. State Final Value with Units: Quote your final calculated value to the required number of significant figures (typically 2 or 3 significant figures in Cambridge & IB) followed by the correct unit.

โš ๏ธ Examiner Warnings & Common Student Pitfalls

Chief Examiner Advice:

On velocity-time graphs, a curved slope indicates non-uniform acceleration. The area of a triangle is 0.5 base height; do not forget the 0.5!


๐Ÿ“ Worked Exam Exemplar (Mark Scheme Breakdown)

Question:

A racing car starts from rest and accelerates uniformly to 28 m/s in 7.0 s. Calculate its acceleration and the distance covered.

Model Answer & Marking Rubric:

Acceleration a = (28 - 0) / 7.0 = 4.0 m/sยฒ. Distance = 0.5 base height = 0.5 7.0 28 = 98 m.


๐Ÿง  Rapid Active-Recall Study Deck (Spaced Repetition)

Test your immediate retention before leaving this page:

  1. Question: What is the fundamental definition associated with Motion: Speed, Velocity & Acceleration Graphs?

Answer: Check the primary learning objective in the checklist above.

  1. Question: Which governing formula links the main physical quantities in this topic?

Answer: `v = \frac{\Delta s}{\Delta t}`.

  1. Question: What classic trap do examiners frequently set on this topic?

Answer: On velocity-time graphs, a curved slope indicates non-uniform acceleration. The area of a triangle is 0.5 base height; do not forget the 0.5!